🎓A few FAQs on JEE(Main) Examination 2025:
Q1) Who is the main body for conducting the JEE(Main) Examination?
A: The Department of Higher Education, Ministry of Education, Government of India has entrusted the responsibility of conducting the Joint Entrance Examination (Main) to the National Testing Agency (NTA) from 2019 onwards.
Q2) Who did conduct the JEE(Main) 2025 Examination?
A: The National Testing Agency (NTA) conducted the Joint Entrance Examination (JEE)-Main 2025 in two different sessions (Session 1 in January 2025 and Session 2 in April 2025). The paper 1 for B.E./B.Tech was conducted in the CBT mode.
Q3) What were the dates for JEE(Main) 2025 Examination?
A: The dates for Session 1 (Paper 1, B.E./B.Tech) were 22, 23, 24, 28 and 29 January 2025 and the dates for Session (Paper 1, B.E./B.Tech) were 02, 03, 04, 07 and 08 April 2025.
Q4) When the result was declared?
A: The result was declared on 18th April 2025.
Q5) In how many languages was the JEE(Main) Exams conducted?
A: The examination was held in 13 different languages such as Assamese, Bengali, English, Gujarati, Hindi, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu and Urdu.
Q6) In how many cities was the JEE(Main) Exams conducted?
A: The JEE-Main 2025 for Session 2 was conducted at 531 unique Examination Centres in 300 Cities.
Q7) Was there any exams cities outside India for JEE-Main 2025?
A: Yes. There are 15 cities where the JEE(Main) Examination 2025 was conducted outside India like in Abu Dhabi, Dubai, Doha City, Kathmandu, Kuala Lumpur, Kuwait, Lagos, Manama, Munich, Muscat, Riyadh, Sharjah, Singapore, Washington, West Java.
Q8) How many candidates did register in January 2025 (Session 1) Examination?
A: Total 13,11,544 candidates registered for January 2025 Examination.
Q9) How many candidates did appear in January 2025 (Session 1) Examination?
A: Total 12,58,136 candidates appeared for January 2025 Examination.
Q10) How many candidates did register in April 2025 (Session 2) Examination?
A: Total 10,61,840 candidates registered for April 2025 Examination.
Q11) How many candidates did appear in April 2025 (Session 2) Examination?
A: Total 9,92,350 candidates appeared for January 2025 Examination.
Q12) What is the Cut-off score for General Category?
A: The Cut-off for General Category is from 100 to 93.1023262 Percentile (97,321 candidates).
Q13) What is the Cut-off score for PwBD Category?
A: The Cut-off for PwBD Category is from 93.0950208 to 0.0079349 Percentile (3,950 candidates).
Q14) What is the Cut-off score for EWS Category?
A: The Cut-off for EWS Category is from 93.0950208 to 80.3830119 Percentile (25,009 candidates).
Q15) What is the Cut-off score for OBC Category?
A: The Cut-off for OBC Category is from 93.0950208 to 79.4313582 Percentile (67,614 candidates).
Q16) What is the Cut-off score for SC Category?
A: The Cut-off for SC Category is from 93.0950208 to 61.1526933 Percentile (37,519 candidates).
Q17) What is the Cut-off score for ST Category?
A: The Cut-off for ST Category is from 93.0950208 to 47.9026465 Percentile (18,823 candidates).
Q18) How many candidates have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 24 (Twenty Four) candidates.
Q19) How many candidates from General Category have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 21 (Twenty One) candidates.
Q20) How many candidates from General-EWS Category have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 1 (one) candidate.
Q21) How many candidates from OBC-NCL Category have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 1 (one) candidate.
Q22) How many candidates from SC Category have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 1 (one) candidate.
Q23) How many candidates from ST Category have obtained NTA Score as Toppers in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 1 (one) candidate (99.9787862 percentile).
Q24) How many candidates from PwBD Category have obtained NTA Score as Toppers in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 1 (one) candidate (99.9619472 percentile).
Q25) How many female candidates have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 2 (Two) candidate.
Q26) How many male candidates have obtained NTA Score of 100 (Toppers) in JEE (Main) 2025 Paper 1 (B.E./B.Tech.)?
A: 22 (Twenty Two) candidate.
Q27) What is the formula for JEE(Main) Score?
A: The NTA Score of a candidate is calculate like, 100 X Number of candidates appeared in the "Session" with raw score EQUAL TO OR LESS than the candidate / (divide by) Total number of candidates who appeared in the "Session". The percentile of candidates appearing in various shifts of the JEE-Main 2025 Session 2 are calculated as per this formula.
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